python requests.get
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1. 获取网页内容
import requests
response = requests.get('http://example.com')
content = response.text
2. 检查请求状态
if response.status_code == 200:
print("请求成功")
else:
print("请求失败，状态码：", response.status_code)
3. 处理异常
try:
response = requests.get('http://example.com')
except requests.exceptions.RequestException as e:
print("请求异常：", e)
import requests
response = requests.get('http://example.com')
content = response.text
2. 检查请求状态
if response.status_code == 200:
print("请求成功")
else:
print("请求失败，状态码：", response.status_code)
3. 处理异常
try:
response = requests.get('http://example.com')
except requests.exceptions.RequestException as e:
print("请求异常：", e)
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建议：检查关键词是否有错别字，或换一个更常见的说法。